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FranciscoMoguel
Beginner
Beginner

Implementacion en Php

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We are studying the possibility of integrating the SecurId support for our PHP application that allows the user to enter their token and authenticate it, which RSA authentication, consequently, returns a result.

 

Is there an example of the API application in PHP?

Is there any documentation to do this in PHP?

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PiersB
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I would recommend looking at the RSA SecurID Authentication API. This is a REST-based interface with examples provided as a part of the "Extras" DVD. There is an interface definition that uses the Open API "YAML" format. This file can be uploaded to "Swagger Editor" and used to generate a PHP client interface for authentication. This interface can be used with Authentication Manager (on-premise) or Access (cloud).

 

Take a look at the RSA SecurID Authentication API Developer's Guide. You'll probably want the interface definition available at RSA SecurID Authentication API Download to generate a PHP interface.

 

There's also an excellent https://community.rsa.com/community/products/securid/blog/2017/07/20/guide-to-getting-started-with-the-am-82-sp1-rest-api-test-app that you may also find useful.

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PiersB
Trusted Contributor Trusted Contributor
Trusted Contributor

I would recommend looking at the RSA SecurID Authentication API. This is a REST-based interface with examples provided as a part of the "Extras" DVD. There is an interface definition that uses the Open API "YAML" format. This file can be uploaded to "Swagger Editor" and used to generate a PHP client interface for authentication. This interface can be used with Authentication Manager (on-premise) or Access (cloud).

 

Take a look at the RSA SecurID Authentication API Developer's Guide. You'll probably want the interface definition available at RSA SecurID Authentication API Download to generate a PHP interface.

 

There's also an excellent https://community.rsa.com/community/products/securid/blog/2017/07/20/guide-to-getting-started-with-the-am-82-sp1-rest-api-test-app that you may also find useful.